A spherical soap bubble has in ternal pr | vedclass

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Question

$\mathrm{P}_{0}-\frac{8 \mathrm{P}_{0}}{9}=\frac{4 \mathrm{S}}{\mathrm{r}_{0}} \Rightarrow \mathrm{P}_{0}=\frac{36 \mathrm{S}}{\mathrm{r}_{0}}$

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Vedclass · Accepted Answer

$3$

Vedclass · Answer

$\mathrm{P}_{0}-\frac{8 \mathrm{P}_{0}}{9}=\frac{4 \mathrm{S}}{\mathrm{r}_{0}} \Rightarrow \mathrm{P}_{0}=\frac{36 \mathrm{S}}{\mathrm{r}_{0}}$

Finally $\mathrm{P}_{	ext {outside }}=0 \Rightarrow \mathrm{P}_{	ext {inside }}=\frac{4 \mathrm{S}}{\mathrm{r}}$

$\mathrm{Now} \quad \mathrm{P}_{1} \mathrm{V}_{1}=\mathrm{P}_{2} \mathrm{V}_{2}$

$\left(\frac{36 S}{r_{0}}ight)\left(\frac{4}{3} \pi r_{0}^{s}ight)=\left(\frac{4 S}{r}ight)\left(\frac{4}{3} \pi r^{3}ight) \Rightarrow r=3 r_{0}$

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