A spherical soap bubble has in ternal pressure $P_0$ and radius $r_0$ and is in equilibrium in an enclosure with pressure ${P_1} = \frac{{8{P_0}}}{9}$ . The enclosure is gradually evacuated . Assuming temperature and surface tension of soap bubble to be fixed find the value of $\frac{{{\rm{final\,\, radius}}}}{{{\rm{initial\,\, radius}}}}$ of soap bubble
$0$
$1$
$3$
$7$
Formation of bubble are in Column - $\mathrm{I}$ and pressure difference between them are given in Column - $\mathrm{II}$. Match them appropriately.
Column - $\mathrm{I}$ | Column - $\mathrm{II}$ |
$(a)$ Liquid drop in air | $(i)$ $\frac{{4T}}{R}$ |
$(b)$ Bubble of liquid in air | $(ii)$ $\frac{{2T}}{R}$ |
$(iii)$ $\frac{{2R}}{T}$ |
A vertical glass capillary tube of radius $r$ open at both ends contains some water (surface tension $T$ and density $\rho$ ). If $L$ be the length of the water column, then:
A liquid column of height $0.04 \mathrm{~cm}$ balances excess pressure of soap bubble of certain radius. If density of liquid is $8 \times 10^3 \mathrm{~kg} \mathrm{~m}^{-3}$ and surface tension of soap solution is $0.28 \mathrm{Nm}^{-1}$, then diameter of the soap bubble is . . . . . . .. . $\mathrm{cm}$.
$\text { (if } g=10 \mathrm{~ms}^{-2} \text { ) }$
Write the equation of excess pressure (pressure difference) for the bubble in air and bubble in water.
Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is